Nun im Themenbereich Chemisches Gleichgewicht
Topic Chemical Equilibrium
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- Chemical products Balance, Speed, Definition (GW-03)Given be One of any kind reaction, The Educated Going on to The Products.
a) How are whole In general The Speed rates defined?
b) What ? Applicable for The Educated, What ? Applicable for The Products? - 1
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- Chemical products Balance, Speed rates (GW-04)Given are the following reactions. Equal each reaction from, So that …
… whole (!) Figures as Coefficients occurring
… for each Substance their Rate of speed (d[X]/(i) the number of) indicated will be.
a) Br2 + H2 ⇄ HBr
b) N2O5 → NO2 + O2
c) A + 2 B → 3 C + 4 D (Yes, I did. Balanced!) - 1
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- collision theory (GW-05)Given are the following: Educated. Give it away to, How many (Theoretical) Clashes It 's to give could between The Educated.
Es Applicable The Adopted, that The reaction rate v Proportional to The Number of The Clashes be
The Commission Other Applicable, that All of them Educated particles with each other reacting must be- A + B
- A, B, D
- F, G, X, Z
- 2A + B
- 3A + 2B
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- RGT-Rule (GW-06)In order to which Factor x increases The Share The molecules, which One Energy of Eating and drinking have, In the case of One of them Temperature increase to 10 Kelvin , please .?
Different Indications:- The Connection between The Temperature and k (Seekers Value In the case of One of them specified Temperature) is given The Commission with the following: Arrhenius equation:
- k = A · e(-Ea/R·T)
- A Constantial, characteristic for The specific reaction
- Eating and drinking, activation energy, 100 kJ/mol, typical Value for many reactions
- R: Gas constant, 8.314 J/(mol·K)
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- law of mass action, 1 (GW-10)Given be One Chemical reaction, The Educated Going So what do you mean? on to The Products. Define for this purpose The equilibrium constant K.
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- law of mass action, 2 (GW-11)What ? three Area values can The equilibrium constant K to accept and How can These Areas Interpreted will be?
Es of which:: Educated ⇄ Products - 1
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- law of mass action, 3 (GW-12)Given are the following reactions. Equal These If necessary from and to define for each (Balanced) reaction This law of mass action.
Notes 1: Forget about it. The Units not and short in so far as How possible
Notes 2: Use for This Balancing whole Figures, No Brof a kind used- H2 + O2 ⇄ H2O
- Br2 + H2 ⇄ HBr
- N2 + H2 ⇄ NH3
- N2O5 ⇄ NO2 + O2
- A + 2 B ⇄ 3 C + 4 D (Yes, I did. Balanced!)
- H2O2 ⇄ H2O + O2
- CH4 + O2 ⇄ CO2 + H2O
- Fe + O2 ⇄ Fe2O3
- N2 + H2 ⇄ NH3
- HCl + NaOH ⇄ NaCl + H2O
- CaCO3 ⇄ CaO + CO2
- KClO3 ⇄ KCl + O2
- Zn + HCl ⇄ ZnCl2 + H2
- AgNO3 + NaCl ⇄ AgCl + NaNO3
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- law of mass action, 4 (GW-13)Given be This Iodine-hydrogen balance:
H2 + I2 ⇄ 2 HI
Lthe island The the following exercises. The Indication 't=0' It should be heated, that The Starting situation Considered will be, 't=GW' that This The system The Commission Now In the Balance is located. It is the same. are The Information to be provided z.B. In the case of H2 as Concentrations (mol/l) to to understand.
Notes: In the case of d) It should be Additionally K Calculated will be.
Notes: In the case of e) be Not yet Additionally K=54.5 given.H2 I2 HI a) t=0 1.0 1.0 0 t=GW 0.3 ? ? b) t=0 2.0 1.0 0 t=GW 1.5 ? ? c) t=0 3.0 0 0 t=GW 2 ? ? d) t=0 9.32 8.05 0 t=GW ? ? 13.5 e) t=0 0 0 0.015 t=GW ? ? ? - 1
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- law of mass action, 5 (GW-14)Given be the following: reaction, All of them Substances are Gaseous: CO + H2O ⇄ CO2 + H2
What ? amount of substance H2 will be of which:, where: with 20 mol CO, 30 mol H2O and 3 mol CO2 Started will be. K of which: 4.05 - 1
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- law of mass action, 6 (GW-15)The Substance ONBr decomposed In the case of 500 ℃ The following masses:
2·ONBr ⇄ 2·NO + Br2
Supposedly, that It 's just … 9 Percentage of the ONBr dissolved. How Large is K, where: It 's just … with 1.0 mol ONBr Started will be? - 1
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- law of mass action, 8 (GW-16)Formulation This MWG (Including Units) for The Education of a) Water and b) NH3 from The Elements.
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- law of mass action, 7 (GW-17)The following: In general Formulated Equation be given. Formulation The equilibrium constant K.
1·A + 2·B ⇄ 3·C + 4·D To the Date and time of which: The Concentration: c(A)=a, c(B)=b, c(C)=c, c(D)=d Formulation The equilibrium constant K for The Case in point, that This Balance …
a) … after on the right Deferred will be.
b) … after Left side Deferred will be.
Notes: Take it . to, that The Changes to the Balance of A x be. - 1
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- Influence chemicals GW, Temperature 1 (GW-20)How It's not The Commission This Chemical Balance by: The Temperature affecting?
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- Influence chemicals GW, Temperature 2 (GW-21)Given be the following: reaction. Assessments whether or not The reaction to the Product I 'm going . Endotherm or exotherm would be. Take it . to, that only The Breach of liability between The Nitrogen atoms in Consideration withdrawn will be I have to ..
reaction: N2O4 ⇄ 2· NO2 - 1
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- Influence chemicals GW, Temperature 3 (GW-22)Given are the following: reactions. How It's not The Commission This Balance by: One Temperature increase (T ↑) respectively. In the case of Reduction of temperature (T ↓) affecting, where: in each case indicated is, whether or not The reaction Endotherm or exotherm is.
- N2O4(g) ⇄ 2·NO2(g) Endothermal reaction
- N2(g) + 3·H2(g) ⇄ 2·NH3(g) Exotherms reaction
- CaCO3(s) ⇄ CaO(s) + CO2(g) Endothermal reaction
- 2·SO2(g) + O2(g) ⇄ 2·SO3(g) Exotherms reaction
- PCl5(g) ⇄ PCl3(g) + Cl2(g) Endothermal reaction
- CO(g) + 2·H2(g) ⇄ CH3OH(g) Exotherms reaction
- NH4Cl(s) ⇄ NH3(g) + HCl(g) Endothermal reaction
- C2H4(g) + H2(g) ⇄ C2H6(g) Exotherms reaction
- CH4(g) + H2O(g) ⇄ CO(g) + 3·H2(g) Endothermal reaction
- H2(g) + Cl2(g) ⇄ 2·HCl(g) Exotherms reaction
- N2(g) + O2(g) ⇄ 2·NO(g) Endothermal reaction
- 2·NO(g) + O2(g) ⇄ 2·NO2(g) Exotherms reaction
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- Influence chemicals GW, Pressure (GW-25)Round to The Influence of the Chemical products GW by: The Pressure.
- With this This Chemical Balance by: The Pressure affecting will be can, must One Fundamental Characteristic The Educated and Products Available. What ? ? And then … Why not? ?
- How modified The Commission This GW In the case of One of them Increase in pressure ?
- How modified The Commission This GW In the case of One of them Pressure reduction ?
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- Influence chemicals GW, Pressure, 2 (GW-26)Given are in each case the following: reactions Including Indications on The state of matter. How modified The Commission This Balance In the case of … Increase of the Pressure (p ↑), Lowering of the Printed (p ↓)
- N2O4(g) ⇄ 2 NO2 (g)
- N2(g) + 3·H2 (g) ⇄ 2·NH3 (g)
- N2(g) + O2(g) ⇄ 2·NO(g)
- 2·SO2(g) + O2(g) ⇄ 2·SO3(g)
- PCl5(g) ⇄ PCl3(g) + Cl2(g)
- NH4Cl(s) ⇄ NH3(g) + HCl(g)
- CaCO3(s) ⇄ CaO(s) + CO2(g)
- CH4(g) + H2O(g) ⇄ CO(g) + 3·H2(g)
- H2(g) + I2(g) ⇄ 2·HI(g)
- CO(g) + 2·H2(g) ⇄ CH3OH(g)
- C2H4(g) + H2(g) ⇄ C2H6(g)
- 2·CO(g) ⇄ CO2(g) + C(s)
- C6H6(l) + 3·H2(g) ⇄ C6H12(l)
- Na2CO3(s) + CO2(g) + H2O(l) ⇄ 2·NaHCO3(s)
- NH4HCO3(s) ⇄ NH3(g) + CO2(g) + H2O(l)
- CuSO45H2O(s) ⇄ CuSO4(s) + 5H2O(g)
- AgCl(s) ⇄ Ag+(aq) + Cl–(aq)
- H2O(l) ⇄ H2O(g)
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- Influence chemicals GW, Concentration (GW-30)Round to The Influence of the Chemical products GW by: The Changes The Concentration.
- How can The equilibrium constant K by: One Changes The Concentration The Educated Responsibility. Products affecting will be? Adopted: p and T Staying constantly.
- Supposedly, The Concentration in education will be (In the Balance) Educated(e) increased. What ? This is happening?
- Supposedly, In the case of One of them reaction will be a Part of (or fully) of the Products Distant. What ? This is happening?
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- Influence chemicals GW, Concentration, 2 (GW-31)Given be the following reaction:
Fe3+ (aq) + 3·SCN– (aq) ⇄ Fe(SCN)3
This Product is Red, This Educated yellow
How modified The Commission The This Balance Responsibility. The Colour The Lthe island In the case of- Added of FeCl3
- Added of KSCN
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- Influence chemicals GW, Chatelier principle (GW-40)How is This Principle of Manufacture in which all the materials used are: ?
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- Influence chemicals GW, Influence The Reaction conditions (GW-41)How effect The Commission the following: Reaction conditions from ? Supplements / corrected the following: Statements:
- One of them. Temperature increase Benefits One Endothermal – Exotherms reaction.
- One of them. Reduction The Temperature Benefits One Endothermal – Exotherms reaction.
- One of them. Increase in pressure Benefits Gas reactions, The of which: Decrease in volume – Increase in volume (c) to be used
- One of them. Reduction of pressure Benefits Gas reactions, The of which: Decrease in volume – Increase in volume (c) to be used
- One of them. Increase The Exploitation One of them reaction can by: Application One of them Educated – Products In the Excess or by: Removing One of them Educated – Products from to the Balance Implemented will be.
- One of them. Catalyst affecting The Location One of them Chemical products Balanced
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- Influence chemicals GW, Cobalt complexes (GW-42)Given be the following: reaction:
[Co(H2O)6]2+ + 6·Cl– ⇄ [CoCl6]4- + 6·H2O
The Water complex is pink coloured, The Chloride complexes blue
The reaction be Endotherm of Left side after on the right.
How It is The Commission The reaction after the following How effect The Commission the following: Reaction conditions from ?- Added of Hydrochloric acid, HCl
- Addition of silver nitrate
- Mixed heating
- Water Admitted
- Fresh or chilled Admitted
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- Influence chemicals GW, Mineral water (GW-43)Mineral water can The following masses Manufacture will be:
H2O (l) + CO2 (g) ⇄ H2CO3 (l)
Explanation with Manufacture in which all the materials used are:, Why? One Open Mineral water bottle on The Time Get away from me. shell, Boring will be and on the It 's over . It 's just … Not yet Water of which: is. - 1
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- Influence chemicals GW, Endothermic or exothermic (GW-44)By 25 ℃ has The Commission a Balance Cessed. When The reaction Now on 0 ℃ Refrigerated will be, increases The Concentration of the Products. question: It is The Reaction (→) Endotherm or exotherm ?
For example:. A + B ⇄ C - 1
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- Influence chemicals GW, Expansion (GW-45)On the which Page will be This GW Deferred, where: This Reaction vessels Expanded will be ? The reaction be:
PF5 (g) ⇄ PF3 (g) + F2 (g) - 1
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- Influence chemicals GW, all reaction (GW-46)Given be The reaction: 1·A(g) + 1·B(g) ⇄ 1·C(g). The Synthesis of the Products be exotherm.
How can by: Variability of the Printed p and The Temperature T as far as possible a lot Product received will be?
What ? for Practical Consequences have The Reaction conditions ? - 1
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