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- Aufgabe: thermo-14
Con il Reddito di: 60 Grammi Zucchero di uva essere x kJ libero. Calcolo di cui: La ΔHof.
Lösung: M(Traubenzucker) = M(C6H12O6) = 180 Grammi
Con 60 g C6H12O6 x kJ, Al fine di una Mol (=180 g) In questo modo 3·x.
ΔHof(C6H12O6) = 3·x kJ/mol.
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