← Zurück zur vorhergehenden Übersicht: Thermodynamik_fr
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- Exercice: thermo-14
Si 60 grammes de sucre de raisin sont vendus, x kJ est libéré. Comptez à partir de cela le ΔHof.
Solution: M(Traubenzucker) = M(C6H12O6) = 180 grammes
Avec 60 g C6H12O6 x kJ, à un Mol (=180 g) donc 3·x.
ΔHof(C6H12O6) = 3·x kJ/mol.
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