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- Exercice: Salze-72
100 grammes de NaCl sont dissous dans 400 ml d'eau. Comptez à partir de cela le produit de solubilité de NaCl
Solution: Il s'applique:
— 1·NaCl ⇄ 1·Na+ + 1·Cl–
— c(NaCl) = c(Na+) = c(Cl–)
— Lp(NaCl) = c(Na+)·c(Cl–)
— c = n/V = m/M/V
— c(NaCl) = 100g/58.5 g/mol / 0.4 l = 4.27 mol/l
— Lp(NaCl) = 4.27 mol/l · 4.27 mol/l = 18.26 mol2/l2
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