This topic has 1 reply, 1 voice, and was last updated 3 months ago by .Viewing 2 posts - 1 through 2 (of 2 total)AuthorPosts April 23, 2024 at 4:01 pm #3178 Frage: (Radio-08) ⓘ 🖶 ausdrucken [klick Frage/Antwort] ◀ – ▶ Berechne die Dichte eines Heliumkernes ( 4He ) Hinweis: Annahmen: — der Heliumkern beansprucht ein kugelförmiges Volumen — Masse Proton = Masse Neutron = 1 u April 23, 2024 at 4:01 pm #3179 Textantwort: Es werden diverse Schritte benötigt: Dichte = m/V = m/(4/3·pi·r3) Masse des Kernes: je 2 Protonen sowie 2 Neutronen, ca. 4 u, 1 u = 1.66·10-27kg, somit 6.64·10-27kg Radius des Heliumkerns: r = 1.2·10-15·4(1/3) = 1.9049·10-15 m V = 4/3·pi·r3) = 2.895·10-44 m3 Dichte = m/V = 2.293·1017 kg/m3 (vgl. Wasser: 1000 kg/m3)AuthorPostsViewing 2 posts - 1 through 2 (of 2 total)You must be logged in to reply to this topic.Log In Username: Password: Keep me signed in Log In Warning: Trying to access array offset on value of type bool in /home/httpd/vhosts/rainer.ch/www_chemieaufgaben_ch/wp1/wp-content/plugins/bbp-style-pack/includes/functions.php on line 2502 Log in / Register