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- Frage: (st-42)
Ein Liter einer Kochsalzlösung wiege 1.34 kg. Welche Konzentration hat die Lösung ?
Textantwort: - Annamhe: 1 Liter Wasser sei 1.0 kg, der Rest also Kochsalz: 340 Gramm
- n=m(NaCl)/M(NaCl) = 340g/58.5 g/mol = 5.81 mol
- c = n/V = 5.81 mol / 1.0 L = 5.81 mol/L
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