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- Frage: (st-34)
10 ml einer 0.02 mol/l Vitamin C Lösung wurden produziert. Welche Masse hatte die eingewogene Masse?
Hinweis: M(Vitamin C) = 176.13 g/mol
Textantwort: - c = n/V = m/M/V
- m = c·V·M
- m = 0.02 mol/l · 0.01 l · 176.13 g/mol = 0.035 g
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