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- Frage: (st-35)
Zu 150 ml einer Lösung mit c = 0.3 mol/l werden 200 ml Wasser gegeben. Welche Konzentration hat die Lösung jetzt?
Textantwort: - c = n/V resp. n = c·V
- n(Lösung) = c·V = 0.3 mol/l·0.15 l = 0.045 mol
- neues Volumen: 150 ml + 200 ml = 350 ml rsp. 0.35 L
- c = n/V = 0.045 mol / 0.35 L = 0.129 mol/L
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