This topic has 1 reply, 1 voice, and was last updated 3 months ago by .Viewing 2 posts - 1 through 2 (of 2 total)AuthorPosts April 23, 2024 at 4:02 pm #3228 Frage: (Salze-903) ⓘ 🖶 ausdrucken [klick Frage/Antwort] ◀ – ▶ 100 Gramm NaCl lösen sich in 400 ml Wasser. Berechne daraus das Löslichkeitsprodukt von NaCl April 23, 2024 at 4:02 pm #3229 Textantwort: Es gilt: — 1·NaCl ⇄ 1·Na+ + 1·Cl– Lp(NaCl) = c(Na+)·c(Cl–) — c(NaCl) = c(Na+) = c(Cl–) — c = n/V = m/M/v — c(NaCl) = 100g/58.5 g/mol / 0.4 l = 4.27 mol/l — Lp(NaCl) = 4.27 mol/l · 4.27 mol/l = 18.26 mol2/l2AuthorPostsViewing 2 posts - 1 through 2 (of 2 total)You must be logged in to reply to this topic.Log In Username: Password: Keep me signed in Log In Warning: Trying to access array offset on value of type bool in /home/httpd/vhosts/rainer.ch/www_chemieaufgaben_ch/wp1/wp-content/plugins/bbp-style-pack/includes/functions.php on line 2502 Log in / Register