← Zurück zur vorhergehenden Übersicht: Salze
- This topic has 1 reply, 1 voice, and was last updated 7 hours, 31 minutes ago by .
Viewing 2 posts - 1 through 2 (of 2 total)
- Posts
- Frage: Salze-72
100 Gramm NaCl lösen sich in 400 ml Wasser. Berechne daraus das Löslichkeitsprodukt von NaCl
Lösung_1: Es gilt:
— 1·NaCl ⇄ 1·Na+ + 1·Cl–
— c(NaCl) = c(Na+) = c(Cl–)
— Lp(NaCl) = c(Na+)·c(Cl–)
— c = n/V = m/M/V
— c(NaCl) = 100g/58.5 g/mol / 0.4 l = 4.27 mol/l
— Lp(NaCl) = 4.27 mol/l · 4.27 mol/l = 18.26 mol2/l2
Viewing 2 posts - 1 through 2 (of 2 total)
- You must be logged in to reply to this topic.