redox, Redux table, Herleitung-1 (Redox-23) The Equation for The Anodic space (pH=14) is In the case of The electrolysis: 4·OH– → O2 + 2·H2O Descriptions The equal to The situation (Including The Electrons) for In total for 6·H2O !

  Aufgabe: Redox-23    

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The Equation for The Anodic space (pH=14) is In the case of The electrolysis:
4·OH^– → O₂ + 2·H₂O
Descriptions The equal to The situation (Including The Electrons) for In total for 6·H₂O !

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Lösung:

1. 4·OH^– → O₂ + 2·H₂O Responsibility. more accurately:
2. 4·OH^– → O₂ + 2·H₂O + 4·e^– // plus 4H⁺
3. 4·OH^– + 4H⁺ → O₂ + 2·H₂O + 2H⁺ 2H⁺ + 4·e^–
4. 4·H₂O → O₂ + 2·H₃O⁺ + 2H⁺ + 4·e^– // plus 2·H₂O
5. 6·H₂O → O₂ + 2·H₃O⁺ + (2H⁺ + 2·H₂O) + 4·e^–
6. 6·H₂O → O₂ + 2·H₃O⁺ + ( 2·H₃O⁺ ) + 4·e^–
7. 6·H₂O → O₂ + 4·H₃O⁺ + 4·e^–

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