redox, Redux table, Herleitung-2 (Redox-24) In the Cathode room (pH=0) is The reaction equation 2·H3O+ + 2·e– → H2 + 2·H2O Forms of this kind to, that on The Right Page 4·OH– appearing.

  Aufgabe: Redox-24    

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In the Cathode room (pH=0) is The reaction equation
2·H₃O⁺ + 2·e^– → H₂ + 2·H₂O
Forms of this kind to, that on The Right Page 4·OH^– appearing.

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Lösung:

1. 2·H₃O⁺ + 2·e^– → H₂ + 2·H₂O // – 2·H⁺
2. 2·H₂O + 2·e^– → H₂ + 2·OH^– // ·2
3. 4·H₂O + 4·e^– → 2·H₂ + 4·OH^–

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