Redox, redux table, Herleitung-2 (Redox-24) In the cathode space (pH=0) the reaction equation is 2·H3O+ + 2·e– → H2 + 2·H2O Forms such that they appear on the right-hand side 4·OH–.

  Exercise: Redox-24    

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In the cathode space (pH=0) the reaction equation is
2·H₃O⁺ + 2·e^– → H₂ + 2·H₂O
Forms such that they appear on the right-hand side 4·OH^–.

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Solution:

1. 2·H₃O⁺ + 2·e^– → H₂ + 2·H₂O // – 2·H⁺
2. 2·H₂O + 2·e^– → H₂ + 2·OH^– // ·2
3. 4·H₂O + 4·e^– → 2·H₂ + 4·OH^–

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