redox, Redux table, Herleitung-3 (Redox-25) In the Cathode room (pH=0) is The reaction equation 4·H2O + 4·e– → 2·H2 + 4·OH– and In the Anodic space (pH=14) 6·H2O → O2 + 4·H3O+ + 4·e– Simplified in so far as How possible !

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In the Cathode room (pH=0) is The reaction equation
4·H₂O + 4·e^– → 2·H₂ + 4·OH^–
and In the Anodic space (pH=14)
6·H₂O → O₂ + 4·H₃O⁺ + 4·e^–
Simplified in so far as How possible !

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Lösung:

1. a) 4·H₂O + 4·e^– → 2·H₂ + 4·OH^–
2. b) 6·H₂O → O₂ + 4·H₃O⁺ + 4·e^–
3. a) + b)
       4·H₂O + 6·H₂O + 4·e^– → O₂ + 4·H₃O⁺ + 4·e^– +2·H₂ + 4·OH^–
       10·H₂O → O₂ + 2·H₂ + 4·H₃O⁺ + 4·OH^–
4. with 2·H₂O → O₂ + 2·H₂ // Both Pages withdrawing
       8·H₂O → 4·H₃O⁺ + 4·OH^–
5. with H₃O⁺ + OH^– → 2·H₂O
       8·H₂O → 6·H₂O + 2·H₂ + O₂
6. 2·H₂O → 2·H₂ + O₂

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