Nun im Themenbereich Stöchiometrie_en
Topic StoichiometryAll problems and solutions as
pdf here.Lernziele resp. Fragengebiete:
- From st-01 : Number of Elements
- From st-10 : Parts and accessories (p,n,e to determine)
- From st-20 : reaction equations Manufacture - Balancing
- From st-30 : isotopes (Look at this. also atomic structure)
- From st-40 : Mol, Unit, molar mass, Number of Mol
- From st-60 : empirical formula
- From st-70 : Calculation, z.B. 10 g H2 + 20 g O2
- From st-80 : Ideal Gases
- From st-90 : Concentration, Density
- This forum has 41 topics, 41 replies, and was last updated sometime ago by .
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- Importance Indices (st-01)What ? is The Indices Responsibility. The Stoichiometric Coefficient?
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- Number of ElementsCalculate in each case The Number of of all Participants Elements the following: Expressions. This first Example is Yes, I did. solved.
(st-02)- a) H2O: 2·H, 1·O
- b) Carbon dioxide
- c) C6H12O6
- d) 7·H2O
- e) 40·C6H12O6
- f) 3 A dozen NH3
- g) 7 Millions O3 (=Ozone)
- h) 2 mol H2O
- i) 13 mol N2
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- Number of complete molecules (st-03)Given are in each case One some Number of Elements. Creepers of which: as far as possible many The (c) Connections. To the Part of can It 's be, that Elements remaining. In the event What ? remaining remaining Give to, How many and which Elements to a lot would be.
- a) H2O, 8·H, 4·O
- b) H2O, 100·H, 100·O
- c) CO2, 20·C, 20·O
- d) C6H12O6, 100·C, 100·H, 100·O
- e) NH3, 200·N, 300·H, 400·C
- f) Fe2O3, 33·Fe, 44·O, 55·F
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- Number of Parts and accessories 1 (st-10)Calculate The Number of The Protons, Neutrons and Electrons
- 7Li
- 13C
- 235U
- 7Li2+
- 82Br–
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- Number of p, n and e, exercise 2 (st-11)Calculate The Number of The Protons, Neutrons and Electrons.
- 7·H2O, with the following Compounds: 3H and 15O
- 3·C6H12O6, with the following Compounds: 2H, 16O, 13C
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- Establishment reaction equation 1Formulation The (Balanced) Combustion reaction One of them Octans (C8H18) (st-20)
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- Establishment reaction equation 3 (st-21)Formulation for The the following exercises The Balanced reaction equation
- Grape sugar will be Burned.
- Place Water from The Elements of which:.
- Place Ammonium nitrate and its salts (NH3) from The Elements of which:.
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- Establishment reaction equation 5 (st-24)One of them. Substance has been Burned and It's receives for each Unknown molecule 9 Water- and 9 Carbon dioxide molecules. In order to which Substance Acting It 's The Commission? Notes to the Searched Substance: The Common molecular formula is CxH2x, Whereas x to to determine would be.
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- Establishment reaction equation 6 (st-25)Equal the following: reaction equations from. The LManufacture in which all the materials used are: to be whole Figures contained
- NaBr ⇄ Na + Br2
- H2 + O2 ⇄ H2O
- N2 + H2 ⇄ NH3
- Al + Br2 ⇄ AlBr3
- C6H12O6 + O2 ⇄ H2O + CO2
- CO + NO ⇄ CO2 + N2
- C8H18 + O2 ⇄ CO2 + H2O
- Fe2O3 + C ⇄ Fe + CO2
- Fe2O3 + CO ⇄ Fe + CO2
- S + O2 ⇄ SO2
- SO2 + O2 ⇄ SO3
- SO3 + H2O ⇄ H2SO4
- Mg + O2 ⇄ MgO
- Fe + O2 ⇄ Fe2O3
- H2 + O2 ⇄ H2O
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- Establishment reaction equation 7 (st-26)Equal the following: reaction equations from. The LManufacture in which all the materials used are: to be whole Figures contained
- H2 + O2 ⇄ H2O
- N2 + H2 ⇄ NH3
- Na + H2O ⇄ NaOH + H2
- K + Cl2 ⇄ KCl
- H2O ⇄ H2 + O2
- SO2 + O2 ⇄ SO3
- CH4 + O2 ⇄ H2O + CO2
- Li2O + H2O ⇄ LiOH
- NH3 + NO ⇄ N2 + H2O
- H2O2 ⇄ H2O + O2
- PCl3 + H2O ⇄ H3PO3 + HCl
- P4 + O2 ⇄ P4O10
- NO2 + O2 +H2O ⇄ HNO3
- C2H6 + O2 ⇄ CO2 + H2O
- P4O10 + H2O ⇄ H3PO4
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- Number of p, n and e (st-30)Calculate The Number of The Protons, Neutrons and Electrons.
- 7·H2O, given are The isotopes 3H and 15O
- 3·C6H12O6, isotopes: 2H, 16O, 13C
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- Importance M (1) (st-41)What ? is The molar mass, For the purposes of this Regulation: 'M'?
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- Importance M (2)How Calculated It's The molar mass 'M', z.B. of Water (H2O)? (st-42)
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- Calculation of moles (st-47)Different calculations to the Subjects mol and Calculation with Large Figures.
- Person A receives One Daily wages of 1000.-, Person B One Annual salary of a half Mol French. Who has The Greater Annual salary? Adopted: Person A work to 365 days In the year. In order to which Factor earned The Person more as The Other Person?
- One of them mol French will be Equivalent to on The Population of the world (about. 8 Billions of dollars Persons) distributed. How a lot French receives each Person?
- The Distance The Sun – Earth is about. 150 Millions Kilometers. How many Atoms with a Diameters of in each case
10-10 m would be necessary, to These Distance How One Woven fabrics of cotton, knitted or crocheted to be removed. Indication The required Atoms in mol. - The pH-Value Right now. seven That's right., that for each Litre Water(-Particles) 10-7 mol more specific Particles of water (H3O+) Available. How many Particles are This So what do you mean? Specifically? And then … How many 'normal' Particles of water are In fact, of which:?
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- Calculation of mould mass 1Calculate The molar mass the following: Connections: (st-48)
- Water
- Carbon dioxide
- C6H12O6
- NaCl
- Fe2O3
- CH4
- H2SO4
- C3H6O
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- Number of MolesCalculate The Number of The Moles the following: Masses: (st-49)
- 9 g Water
- 88 g Carbon dioxide
- 900 g C6H12O6
- 175.5 g NaCl
- 320 g Fe2O3
- 9 kg CH4
- 2 Of which: H2SO4
- 2 g C3H6O
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- empirical formulas (st-60)Given are the following: Connections. Calculate The Percentage Shares in bulk (Percentage by weight) The Elements the following: molecules:
- Water
- Carbon dioxide
- CH4
- NH3
- C2H6O
- C6H12O6
- H2SO4
- C3H6O
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- stoichiometry In general (st-70)How It works. stoichiometry? On the What ? must It's The Commission In particular: eight, In the case of One of them stoichiometry Accounts? How functioning The Texting tasks In the case of The stoichiometry Yes, I did. It 's back .? There is It 's There you go. a Application patterns? (Number of molecules Calculation, How a lot Grams to be created, How a lot Grams needs It 's and so on.)
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- Calculate with reaction equations 1Es to be 100 Grams Water Manufacture will be. Place (st-71)
a) … The reaction equation on
b) … Calculate How a lot Grams The Individual Components Required will be - 1
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- Calculate with reaction equation 2 (st-72)Es will be 64 Grams Methane Burned (CH4). How a lot Grams The different Products to be created?
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- Calculate with reaction equation 3 (st-73)Place 51 Grams Ammonium nitrate and its salts (NH3) from The Elements I 'm here, How a lot Grams The Individual Educated will be Required?
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- Calculate with reaction equation 4 (st-74)By One of them reaction to be created 54 Grams Water. What ? Volumes takes This Water …
- … In the Liquid State of operation a?
- … In the Gaseous State of operation In the case of Normal conditions a?
- … In the Gaseous State of operation In the case of a Pressure of 3 bar and 70℃ a?
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- Calculate with reaction equation 5 (st-75)Round to The Manufacture of Fresh or chilled.
In order to Manufacture of 150 g Fresh or chilled will be 70 g Sodium Provided, The with Chlorine to Sodium chloride reacting to be. What ? Weight remaining From the Sodium after (Stoichiometric) Application remaining? - 1
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- Calculate with reaction equation 55 (st-76)Different exercises round to This Chemical Calculation.
- Lightweight exercises
- a) The Formula for Methyl alcohol is CH3OH. What ? Molecular mass owned a such as molecule?
- b) How many Oxygen atoms contained 1 g O2-Moleküle?
- c) How many Atoms contains 1g Helium gas?
- d) How a lot Grams corresponding to 1 mol Sulphur, 1 mol Sodium and 1 mol Water?
- e) How Large is The Weight of:
0.5 mol Carbon dioxide (Formula CO2)
0.1mol Sulphuric acid (Formula H2SO4)? - f) How Large is The Molecular mass One of them Substance, where: 0.87 mol of you 24.36 g Weighing?
- g) How a lot C-Atoms contained 24 g Carbon?
- h) How many Oxygen atoms contained 1 g Ozone (O3)? Indication in Mol (n) and 'real' Number of
- Half weight exercises
- i) How a lot Grams Water It is The Commission In the case of The Incineration of 100 g Methane (CH4)?
- j) Men and boys (Pb304) It's not The Commission from Lead oxide (PbO) by: Oxidation with Oxygen represent. Calculate The Weight to Lead oxide, The to the Manufacture of 100 kg Men and boys Required is.
- k) Alcohol (C2H5OH) will be Usually by: Fresh or chilled of Glucose (C6H12O6) Presented, accordingly The reaction equation :
Glucose molecule –> 2 Alcohol molecules + 2 Carbon dioxide molecules
How a lot kg Alcohol to leave The Commission from 2 kg Glucose winning? - Weight exercises
- l) How a lot Grams Zinc sulphide(ZnS) received We are In the case of The Implementation of 200 g Zinc with 1000 g Sulphur (S8)?
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- Calculate with reaction equation 6One of them Car Consumed on 100 km 10 Litre Diesel. (st-77)
a) Calculate The Weight of the of which: Carbon monoxide.
b) Calculate This Volumes which This The following is an extract: Carbon dioxide It takes. Adopted: Standard conditions
Adopted: Diesel of which: from One of them only Component: C15H32 - 1
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- Calculate with reaction equation 7 (st-78)Calculate The Masses of all Participants Particles the following: reaction equations
- PbO + C → Pb + CO2, given be 0.528 g C.
M(PbO) = 223.2 g/mol, M(Pb) = 207.2 g/mol, M(CO2) = 44 g/mol - NaCl → Na + Cl2, given be 100 g Na.
M(NaCl) = 58.5 g/mol, M(Cl2) = 71 g/mol - Fe + O2 → Fe2O3, given be 100 Of which: Iron and steel.
M(O2) = 32 g/mol, M(Fe2O3) = 159.6 g/mol - Sodium (Na) and Chlorinated gases (Cl2) to be created by: One Fusion electrolysis (special Technical Procedures) from Sodium chloride (NaCl). Place The reaction equation on and Calculate, How a lot Grams Sodium chloride used will be must be, to 100.0 g Sodium to received.
- Calcium carbide (CaC2) is One Solids, The with Water a Containing by weight: Gas developed, has been Previously also for Machinery for the manufacture of lamps Required.
reaction equation: Ca + 2·C → CaC2
How a lot kg CaC2 receives It's, where: It's 50 kg Ca used? How a lot kg Carbon will be For that Required.
- PbO + C → Pb + CO2, given be 0.528 g C.
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- gas equation 2 (st-81)Why ? He speaks It's In fact, of The -Apop-ideal apop- gas equation?
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- Different calculations, Ideal Gas law (st-84)Different calculations
- One of them. Gas sample takes In the case of a Pressure of 75 kPa a Volumes of 360 Milligrams a. What ? Volumes takes The Sampling In the case of The equal to Temperature of which: a Pressure of 100 kPa a ?
- This Volumes One of them Gas sample is 462 Milligrams In the case of 35 ℃ and 115 kPa. What ? is This Volumes In the case of Normal conditions ?
- How a lot Litre CO (g) In the case of Normal conditions measured, will be Required, to 1.0 kg Rust (Fe2O3) The following masses to be implemented:
Fe2O3 + CO → Fe + CO2 - One of them Mol One of them Gases claimed In the case of Normal conditions 22.4 Litre. Calculate The Length of pages of the Mol-Wof which:.
- How a lot In kilograms Air are in a Classrooms?
Assumptions: 180 m3, 20 ℃ 100'000 Pa, Air 80% N2, 20% O2
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- Concentration, exercise 1233 (st-90)Different calculations round to The Concentration.
- 5 Grams Fresh or chilled will be in a Litre Water given. What ? Concentration has The Lthe island?
- 18 g C6H12O6 will be in 120 Milligrams Water solved. What ? Concentration has The Lthe island?
- 10 Milligrams One of them 0.02 mol/l Vitamins C Lthe island have been Produced. What ? Weight had The weighted Weight?
Notes: M(Vitamin C) = 176.13 g/mol - Es to be 100 Milligrams One of them Magnesium bromide solution (MgBr2) with The Concentration of c = 0.02 mol/L Manufacture will be.
How can These Lthe island In the Chemical laboratory Manufacture will be? - One of them Litre One of them Cooking salt solution Weighing 1.34 kg. What ? Concentration has The Lthe island?
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- Concentration, exercise 12 (st-92)1 Grams Gold It should be on The Oceans and seas distributed will be. How many Gold atoms are The Commission for each Litre.
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- Concentration, exercise 10 (st-93)Calculate The Concentration of Household sugar (C12H22O11), in One of them Cup Coffee (150 Milligrams), where: in it. a WOther sugar (m = 7.7 g) dissolved will be.
Additionally: How many molecules Caffeine (C8H10N4O2) are The Commission after a Coffee In the KManufacture, where: in One of them Cup Coffee 80 mg of which: dissolved were? - 1
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- Concentration, exercise 4 (st-94)Different calculations round to The Concentration.
- To the 150 Milligrams One of them Lthe island with c = 0.3 mol/l will be 200 Milligrams Water given. What ? Concentration
- To the 300 Milligrams One of them Lthe island with c = 0.3 mol/l will be 200 Milligrams One of them (equal to) Lthe island with c= 0.5 mol/L given. What ? Concentration has The Lthe island Now .?
- Given be 1.5 L One of them Cooking salt solution with c = 0.15 mol/L.
Well, you know what? to be But 2.0 L One of them Cooking salt solution with c = 0.3 mol/L Manufacture will be. How many Grams Fresh or chilled and Water must to the (c) Cooking salt solution Not yet Additionally Added will be.
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