Nun im Themenbereich Redox_en
Topic Redox
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- oxidation numbers (Redox-01)Fixed The oxidation numbers of all Participants Atoms
- H2
- F2
- Na+
- S2-
- H2O
- Fe3O4
- CH4
- CH3F
- CHF3
- CH4O
- N2O4
- NO
- HNO3
- H3O+
- NH+4
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- redox, Definitions (Redox-10)Define the following: concepts In the Connection Electron charge – Electron recording.
- Reduction
- Oxidation
- reducing agent
- oxidizing agent
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- redox, Definitions, oxidation numbers (Redox-11)Define the following: concepts In the Connection with The oxidation numbers
- Reduction
- Oxidation
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- redox, Apply The Definitions (Redox-12)Methane, CH4, will be Burned.
- Formulation The reaction equation
- Fixed All of them oxidation numbers
- Turn around . The concepts Reduction and Oxidation to
- It is O2 a oxidizing agent or reducing agent. Reasons The Election.
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- electrolysis – One redox reaction (Redox-13)It is The electrolysis of Water One Sgold base reaction or One Redox reaction? Reasons!
Notes: The electrolysis is The Decomposition of the Water in his Components with Help of Electricity:
2·H2O ⇄ 2·H2 + 1·O2 - 1
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- redox, Redux table, Electrode potentials (Redox-14)Respondents the following: questions. Give it away in each case as Proof of this also Examples to.
- Are Manufacture from materials of any heading Always reducing agent?
- Are Manufacture from materials of any heading Always oxidizing agent?
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- redox, reaction 3 (Redox-15)Given be the following Equation. Equal They from, determining All of them oxidation numbers, Where finds The Oxidation Instead of, Where The Reduction?
Ag + HNO3 ⇄ AgNO3 + NO2 + H2O - 1
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- redox, reaction 4 (Redox-16)Given be the following, Yes, I did. Balanced reaction equation. Fixed All of them oxidation numbers. Where finds The Oxidation Instead of, Where The Reduction?
3SO3^2- + Cr2O7^2- + 8H^+ -> 2Cr^3+ + 3SO4^2- + 4H2O - 1
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- redox, reaction 5 (Redox-17)Given are the following, Yes, I did. Balanced reaction equations. Fixed All of them oxidation numbers. Where finds The Oxidation Instead of, Where The Reduction? In the event The Commission The oxidation number not Changes, This is it. Give This also to.
{a: } 3SO3^2- + Cr2O7^2- + 8H^+ -> 2Cr^3+ + 3SO4^2- + 4H2O{b: } N2H4 + 4Fe(CN)6^3- + 4OH^- -> N2 + 4Fe(CN)6^4- + 4H2O{c: } Ru + 6Cl^- + 3NO3^- + 6H^+ -> RuCl6^3- + 3NO2 + 3H2O{d: } ClO3^- + 3SO2 + 3H2O -> 3SO4^2- + Cl^- + 6H^+{e: } 3H2S + 2HNO3 -> 2NO + 3S + 4H2O{f: } KSCN + 4H2O + 4I2 -> KHSO4 + 7HI + ICN - 1
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- redox, reaction 6 (Redox-18)Given be the following, Yes, I did. Balanced reaction equation. Fixed All of them oxidation numbers. Where finds The Oxidation Instead of, Where The Reduction?
What ? is Here you go. In particular: ?Cl2 + 2NaOH -> NaCl + NaClO + H2O - 1
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- redox, Multiple choices (Redox-20)Respondents the following: questions with Yes , it is . or No , it 's not .. Yes , I did . That's right., that The complete question (So what do you mean? also If possible of which: Additional levies) correctly is.
In the the following will be of the following: Table out of business:
Li → Li+ E= -3.05 V
K → K+ E = -2.93 V
…
2·F– → F2 E = +2.87 V- reducing agent Standing in The Redux table Left side.
- oxidizing agent Standing in The Redux table on the right.
- The Commission Continued on top in The Redux table a oxidizing agent (on the right) is, the more Stronger is It 's.
- By One of them Oxidation will be Electrons From the oxidizing agent Submitted.
- All of them Manufacture from materials of any heading can roasting.
- One of them. Substance will be Oxidated, where: They …
Protons is emitted.
Protons is absorbed.
Electrons is emitted.
Electrons is absorbed. - On the The Anode finds Always The Oxidation Instead of.
- One of them strong oxidizing agent has One small Tendency, Electrons to be included.
- One of them strong oxidizing agent has One large Tendency, self Reduced to will be.
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- redox, reaction 1 (Redox-21)Cinnamon (Sn) will be in One Acid Lthe island given. Notes The reaction equation, Oxidation and Reduction. It is The SYour Here you go. a oxidizing agent ?
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- redox, reaction 2 (Redox-22)One of them Piece of work Silver (Ag) will be in One 1 mol/Liter NaOH given. Notes The reaction equation, Oxidation and Reduction.
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- redox, Redux table, Herleitung-1 (Redox-23)The Equation for The Anodic space (pH=14) is In the case of The electrolysis:
4·OH– → O2 + 2·H2O
Descriptions The equal to The situation (Including The Electrons) for In total for 6·H2O ! - 1
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- redox, Redux table, Herleitung-2 (Redox-24)In the Cathode room (pH=0) is The reaction equation
2·H3O+ + 2·e– → H2 + 2·H2O
Forms of this kind to, that on The Right Page 4·OH– appearing. - 1
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- redox, Redux table, Herleitung-3 (Redox-25)In the Cathode room (pH=0) is The reaction equation
4·H2O + 4·e– → 2·H2 + 4·OH–
and In the Anodic space (pH=14)
6·H2O → O2 + 4·H3O+ + 4·e–
Simplified in so far as How possible ! - 1
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- redox, Redux table, Herleitung-4 (Redox-26)Alternative Derivatives and derivatives The previously Equation. Starting:
a) H2 + 2·H2O → 2·H3O+ (pH=7, -0.42 V)
b) 4·OH– → O2 + 2·H2O (pH=7, 0.83V)
The reaction would be Yes , it is . Mountains Responsibility. Down below Left side after on top on the right. Formulation The total reaction with to the Notes, that The reaction ·2 made will be I have to ..
The second question … Why? ·2 - 1
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- Iron bromide (Redox-27)After a Try it . is One Zinc sulphate solution with Copper ions polluted. How can The Copper ions Efficiency Distant will be? Why ? It works. One Distilled and Filtration not?
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- redox, Redux table, exercise 2 (Redox-29)Assessments on the basis The Redux table, whether or not the following: reactions possible are.
- Ag in Copper sulphate
- Silver nitrate in Copper
- You can Let it go. (basic) Bromine with Iron and steel reacting. Bromine Lying In the Excess before.
- Magnesium in 1 M HCl
- How can from Silver nitrate This Silver in more solid Form gained will be. As Aids are It 's just … Sof which: or bases permitted.
- Gold It should be in One of them Lthe island dissolved will be. Give it away One Suitable Variation to.
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- redox, Redux table, It’s not funny 1 (Redox-30)
- How is The Other goods of heading 8401 Equation ?
- How is The Other goods of heading 8401 Equation for diluted LManufacture in which all the materials used are: of the equal to Flat-rolled products of iron or steel
- Given be One concentrated Cu2+-Lösung and One diluted Cu2+-Lösung, in which in each case One Cu-Electrodes Rags. LManufacture in which all the materials used are:, It 's just … Separated by: a For the purposes of this Regulation:, with each other Connected are? Use of which: other The concept Reduction, Oxidation, Court of Justice to The Catheter Responsibility. Anode.
- How Calculated The Commission The Tensions between two Different Half-cells ?
- Calculate This Potential One of them Silver cell with The Concentration of 0.1 mol/l
- Calculate This Potential One of them Silver cell with The Concentration of 0.01 mol/l
- How Large is The Tensions between two Semicells with The Tensions 0.1 Responsibility. 0.01 mol/L
- One of them. Zinc half cell will be to The Factor 1000 diluted. Calculate The Voltage decrease Responsibility. This new Potential.
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- redox, Redux table, It’s not funny 2 (Redox-31)Calculate in each case This Potential for the following: given LManufacture in which all the materials used are: Responsibility. reactions. Given be also:
E = Eo + 0.059/n · log(ca(Oxidierte Form)/ cb(Reduzierte Form))- Zn → Zn2+, c(Zn2+) = 0.1 mol/L
- 2 Cl– → Cl2, c(Cl–) = 2 mol/L
- Mn2+ + 12 H2O → MnO–4 + 8 H3O+ , c(Mn2+) = x, c(MnO–4) = y
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- redox, Redux table, It’s not funny 3 (Redox-32)What ? Tensions Calculated The Commission for This The Commission shall adopt delegated acts in accordance with Article 21 of this Regulation., where: In the case of 298 K The Concentration The Zinc sulphate solution 0.001 mol/L and The The Copper sulphate solution 0.8 mol/L is.
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- redox, Redux table, It’s not funny 4 (Redox-33)a) What ? Tensions Calculated The Commission for This The Commission shall adopt delegated acts in accordance with Article 21 of this Regulation., where: In the case of 298 K The Concentration The Zinc sulphate solution and The The Copper sulphate solution in each case 1 mol/L is. Give it away for this purpose The In general Valid Equation to.
b) Calculate The new Tensions where: Adopted will be, that after in each case 15 Minutes The Concentrations The Commission in each case to 0.1 mol/L amended have. - 1
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- redox, Car batteries (Redox-40)Explanation In the case of One of them Car batteries the following: Proceedings:
- Unloading
- Shopping
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- redox, Amper hours, Oh, my God (Redox-41)By One of them Car batteries is the following: Additionally: 100 Oh, my God., 12 v
How many Electrons (in mol) can So what do you mean? within 5 h Flow? - 1
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- redox, Car batteries, Turnover (Redox-42)One of them. Car batteries be full loaded and Containing 1.5 Litre One of them 30% Mixtures of sulphuric acid. -the following points shall be added:- be The Concentration It 's just … Not yet 20%. How a lot Lead Responsibility. Lead oxide has been in each case Implemented?
Notes: The Density The 30% Sulphuric acid-Lthe island of which:1.84 g/cm3 . Unloading be The Density Right now. Large. - 1
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- electrolysis – One redox reaction, LManufacture in which all the materials used are: (Redox-50)Supplements The the following LOats and oats by: Useful Content. By The Considered reaction Acting It 's The Commission to The electrolysis of Water.
… loaded Oxonium ions (…) Traveling In the Electrical Field to The … loaded Electrodes (Catheter), Where They in each case a Electron … . In doing so to be created Hydrogen atoms, The The Commission with a Other, by: … of which: H-Atomic energy to a Hydrogen molecule to unite. It 's all right . Staying Water molecules.
The Separated, Gas-shaped Hydrogen increases to The Catheter on, Whereas The Cathode room … will be. The negative loaded Hydroxide anions Traveling to the … Anode, Whereas The Commission Hydroxidions with Protons (H+ Responsibility. H3O+) to Water Neutralizing or The Commission to The Anode of which: … to Oxygen conversion.
Also Here you go. increases The Separated Oxygen as Gas to The Anode on, At the same time will be The Anodic space … . The of which: Protons Traveling in Direction … – by analogy to The Measures to be taken In the Cathode room. - 1
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- redox, electrolysis, 1 (Redox-51)Copper will be Electrolytic from Cu2+ -Ⅰons gained. In One of them Electrolytic cells will be One Cu2+ -withdrawn Lthe island
30 min with One of them Power intensity ofI = 2.5 A Electrolytic. Calculate The Separated Weight m(Cu) In the case of a Degree of electrolysis of 92.5%.
Notes 1: m/M = I·t/(z·F)
Notes 2: In a the first Step by step of One Effectiveness of 100% Going out.
Notes : Identical exercise also At the same time, Subjects salts. - 1
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- redox, electrolysis, 2 (Redox-52)One of them. Silver nitrate-Lthe island will be In the case of One of them Power intensity of 2.54 A Electrolytic. What ? Weight to Silver is divorced The Commission in 45 Minutes from. The Effectiveness of which: 90%.
Notes : Identical exercise also At the same time, Subjects salts. - 1
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- redox, electrolysis, 3 (Redox-53)15 m2 One of them Metal surface area to be with One of them 35 µm thick Manufacture from materials of any heading Coated will be. Chromes has One Density of
7.15 g/cm3 .
a) Calculate The Weight Chromes, which discharged will be must.
b) The Separation occurred from One of them CrO3 – Lthe island. How long must Electrolytic will be, where: The Power intensity 450 A and The Effectiveness 90% of which:.
Notes : Identical exercise also At the same time, Subjects salts. - 1
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- redox, electrolysis, 4 (Redox-54)How long must a Electricity The Strength 0.45 A Flow, with from One of them CuCl2 Lthe island 3.5 g Copper discharged will be?
Notes : Identical exercise also At the same time, Subjects salts. - 1
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- redox, electrolysis, 5 (Redox-55)How long must a Electricity The Strength 10 A Flow (about. more common -Appropriate expenditure-), to Electrons The Total mass 1 kg by: The Line cross-section Wandered are?
Notes m(e–) = 9.1·10-31 kg, Loading 1e– = 1.602·10-19 C
Notes : Identical exercise also At the same time, Subjects salts. - 1
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- redox, electrolysis, 6 (Redox-56)One of them. Shell with One of them Surface of 120 cm2 It should be by: electrolysis One of them Silver nitrate solution One 0.2 mm thick Silver transhipment received. Calculate The For that required Time, where: The Power intensity 10 A is. The Density of the Silvers and silvers of which:
10.5 g/cm3 .
Notes : Identical exercise also At the same time, Subjects salts. - 1
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- redox, electrolysis, 7 (Redox-57)Calculate The Thick The Copper layer, The a Electricity The Strength 5.8 A in 3h on One of them Bullets with to the Radius 8.3 cm Equivalent to – It 's goodbye ..
Notes 1: Surface One of them Bullets be 4·pi·r2
Notes 2: The The Commission shall adopt implementing acts. has been with One of them Copper sulphate solution carried out
Notes 3: Dichte(Cu) = 8.9 g/cm3
Notes : Identical exercise also At the same time, Subjects salts. - 1
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- redox, electrolysis, 8 (Redox-58)From One of them Copper sulphate solution to be 800 mg Copper In the case of I=180mA to The Catheter discharged will be. Calculate a) The Period of time The electrolysis and b) determining This Volumes to Oxygen, This of which: Normal conditions (298 K, 101300 N/m2) At the same time is generated.
The Common gas equation is p·V=n·R·T, WhereasR = 8.314 J/molK .
Notes : Identical exercise also At the same time, Subjects salts. - 1
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